Question

$\begin{align*} & 3.xy-4z=0\\ & 4yz-5x=0\\ & 5\times z-by=0\\ & xy.z=?\end{align*}$

Answer 1

$xy=\frac{4z}{3},\quad yz=\frac{5x}{4},\quad xz=\frac{6y}{5}$ eşitlikleri taraf tarafa çarpılırsa $(xyz)^2=\frac{4z.5x.6y}{3.4.5}\Rightarrow xyz=2$ olur.