√a+√b=√a+√b
2√a+√b=?
√a+√b=√a+√b⇒a+√b=a+b+2√a⋅√b⇒2√a+√b=1
(√a+√b)2=(√a+√b)2⇒a+√b=a+b+2√a.b⇒√b=b+2√a.b
⇒√b=√b(√b+2√a)→1=√b+2√a olacaktır.