Question

$p\wedge[(p'\vee q)\wedge q']$ en sade hali

Answer 1

$$p\wedge [(p'\vee q)\wedge q']\equiv p\wedge [(p'\wedge q')\vee (q\wedge q')]\equiv p\wedge [(p'\wedge q')\vee 0]\equiv p\wedge (p'\wedge q')$$

$$\equiv$$

$$(p\wedge p')\wedge q'$$

$$\equiv$$

$$0\wedge q'$$

$$\equiv$$

$$0$$ Yani çelişki (hepyanlış).