Question

$\sin \left( 2x-\dfrac {\pi } {3}\right) =\cos \left( x+\dfrac {\pi } {6}\right)$

denklemin köklerinden biri ?

Answer 1

genel trigonometrı çözümünden yazdıgın referans cevaba göre


$sin(2x-60)=cos(x+30)=sin(60-x)$
olur


$2x_1-60$    :        $60-x_1+2.\pi.k$


$2x_2-60$    :        $180-(60-x_2)+2.\pi.k$


yani



$x_1$    :        $40+\dfrac{2.\pi.k}{3}$


$x_2$    :        $180+2.\pi.k$

Answer 2

İp ucu: $2x-(\pi/3)+x+(\pi/6)=(\pi/2)+2\pi.k$ dır.